# Problem of the Week

## Updated at Apr 26, 2021 11:30 AM

This week's problem comes from the calculus category.

How can we find the derivative of $${x}^{3}+\ln{x}$$?

Let's begin!

$\frac{d}{dx} {x}^{3}+\ln{x}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dx} {x}^{3})+(\frac{d}{dx} \ln{x})$2 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$3{x}^{2}+(\frac{d}{dx} \ln{x})$3 The derivative of $$\ln{x}$$ is $$\frac{1}{x}$$.$3{x}^{2}+\frac{1}{x}$Done3*x^2+1/x