# Problem of the Week

## Updated at Nov 1, 2021 4:12 PM

How can we solve the equation $$\frac{5}{3}(v+2)+4=\frac{32}{3}$$?

Below is the solution.

$\frac{5}{3}(v+2)+4=\frac{32}{3}$

 1 Simplify  $$\frac{5}{3}(v+2)$$  to  $$\frac{5(v+2)}{3}$$.$\frac{5(v+2)}{3}+4=\frac{32}{3}$2 Subtract $$4$$ from both sides.$\frac{5(v+2)}{3}=\frac{32}{3}-4$3 Simplify  $$\frac{32}{3}-4$$  to  $$\frac{20}{3}$$.$\frac{5(v+2)}{3}=\frac{20}{3}$4 Multiply both sides by $$3$$.$5(v+2)=\frac{20}{3}\times 3$5 Cancel $$3$$.$5(v+2)=20$6 Divide both sides by $$5$$.$v+2=\frac{20}{5}$7 Simplify  $$\frac{20}{5}$$  to  $$4$$.$v+2=4$8 Subtract $$2$$ from both sides.$v=4-2$9 Simplify  $$4-2$$  to  $$2$$.$v=2$Donev=2