Problem of the Week

Updated at May 23, 2022 11:41 AM

For this week we've brought you this algebra problem.

How can we compute the factors of \(30{n}^{2}-59n+28\)?

Here are the steps:



\[30{n}^{2}-59n+28\]

1
Split the second term in \(30{n}^{2}-59n+28\) into two terms.
\[30{n}^{2}-24n-35n+28\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[6n(5n-4)-7(5n-4)\]

3
Factor out the common term \(5n-4\).
\[(5n-4)(6n-7)\]

Done