Problem of the Week

Updated at Feb 13, 2023 2:18 PM

This week we have another algebra problem:

How can we factor \(6{y}^{2}-48y+42\)?

Let's start!



\[6{y}^{2}-48y+42\]

1
Find the Greatest Common Factor (GCF).
GCF = \(6\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[6(\frac{6{y}^{2}}{6}+\frac{-48y}{6}+\frac{42}{6})\]

3
Simplify each term in parentheses.
\[6({y}^{2}-8y+7)\]

4
Factor \({y}^{2}-8y+7\).
\[6(y-7)(y-1)\]

Done
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