# Problem of the Week

## Updated at Feb 27, 2023 11:21 AM

For this week we've brought you this equation problem.

How can we solve the equation $$\frac{4(z-3)(z-3)}{5}=0$$?

Here are the steps:

$\frac{4(z-3)(z-3)}{5}=0$

 1 Use Product Rule: $${x}^{a}{x}^{b}={x}^{a+b}$$.$\frac{4{(z-3)}^{2}}{5}=0$2 Multiply both sides by $$5$$.$4{(z-3)}^{2}=0\times 5$3 Simplify  $$0\times 5$$  to  $$0$$.$4{(z-3)}^{2}=0$4 Divide both sides by $$4$$.${(z-3)}^{2}=0$5 Take the square root of both sides.$z-3=0$6 Add $$3$$ to both sides.$z=3$Donez=3