Problem of the Week

Updated at Sep 4, 2017 9:39 AM

To get more practice in algebra, we brought you this problem of the week:

How can we factor \(6{x}^{2}+3x-30\)?

Check out the solution below!



\[6{x}^{2}+3x-30\]

1
Find the Greatest Common Factor (GCF).
GCF = \(3\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[3(\frac{6{x}^{2}}{3}+\frac{3x}{3}-\frac{30}{3})\]

3
Simplify each term in parentheses.
\[3(2{x}^{2}+x-10)\]

4
Split the second term in \(2{x}^{2}+x-10\) into two terms.
\[3(2{x}^{2}+5x-4x-10)\]

5
Factor out common terms in the first two terms, then in the last two terms.
\[3(x(2x+5)-2(2x+5))\]

6
Factor out the common term \(2x+5\).
\[3(2x+5)(x-2)\]

Done
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