Problem of the Week

Updated at Oct 8, 2018 8:31 AM

For this week we've brought you this equation problem.

How would you solve the equation \(\frac{4y+2}{3}-5=1\)?

Here are the steps:



\[\frac{4y+2}{3}-5=1\]

1
Factor out the common term \(2\).
\[\frac{2(2y+1)}{3}-5=1\]

2
Add \(5\) to both sides.
\[\frac{2(2y+1)}{3}=1+5\]

3
Simplify  \(1+5\)  to  \(6\).
\[\frac{2(2y+1)}{3}=6\]

4
Multiply both sides by \(3\).
\[2(2y+1)=6\times 3\]

5
Simplify  \(6\times 3\)  to  \(18\).
\[2(2y+1)=18\]

6
Divide both sides by \(2\).
\[2y+1=\frac{18}{2}\]

7
Simplify  \(\frac{18}{2}\)  to  \(9\).
\[2y+1=9\]

8
Subtract \(1\) from both sides.
\[2y=9-1\]

9
Simplify  \(9-1\)  to  \(8\).
\[2y=8\]

10
Divide both sides by \(2\).
\[y=\frac{8}{2}\]

11
Simplify  \(\frac{8}{2}\)  to  \(4\).
\[y=4\]

Done
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