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Problem of the Week

Updated at Nov 5, 2018 11:02 AM

How would you solve \(\frac{20}{x}-2-{x}^{2}=4\)?

Below is the solution.



\[\frac{20}{x}-2-{x}^{2}=4\]

1
Multiply both sides by \(x\)
\[20-2x-{x}^{3}=4x\]

2
Move all terms to one side
\[20-2x-{x}^{3}-4x=0\]

3
Simplify \(20-2x-{x}^{3}-4x\) to \(20-6x-{x}^{3}\)
\[20-6x-{x}^{3}=0\]

4
Factor \(20-6x-{x}^{3}\) using Polynomial Division
How?

\[(-{x}^{2}-2x-10)(x-2)=0\]

5
Solve for \(x\)
\[x=2\]

6
Use the Quadratic Formula
How?

\[x=\frac{2+6\imath }{-2},\frac{2-6\imath }{-2}\]

7
Collect all solutions from the previous steps
\[x=2,\frac{2+6\imath }{-2},\frac{2-6\imath }{-2}\]

8
Simplify solutions
\[x=2,-1-3\imath ,-1+3\imath \]

Done
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