Problem of the Week

Updated at Feb 8, 2021 2:51 PM

For this week we've brought you this calculus problem.

How can we find the derivative of \(\csc{y}+3y\)?

Here are the steps:



\[\frac{d}{dy} \csc{y}+3y\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dy} \csc{y})+(\frac{d}{dy} 3y)\]

2
Use Trigonometric Differentiation: the derivative of \(\csc{x}\) is \(-\csc{x}\cot{x}\).
\[-\csc{y}\cot{y}+(\frac{d}{dy} 3y)\]

3
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[-\csc{y}\cot{y}+3\]

Done