Problem of the Week

Updated at Sep 5, 2022 12:09 PM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of $$\csc{v}+9v$$?

Check out the solution below!

$\frac{d}{dv} \csc{v}+9v$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dv} \csc{v})+(\frac{d}{dv} 9v)$2 Use Trigonometric Differentiation: the derivative of $$\csc{x}$$ is $$-\csc{x}\cot{x}$$.$-\csc{v}\cot{v}+(\frac{d}{dv} 9v)$3 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$-\csc{v}\cot{v}+9$Done-csc(v)*cot(v)+9