Problem of the Week

Updated at Jun 5, 2023 9:31 AM

For this week we've brought you this algebra problem.

How would you find the factors of \(20{u}^{2}+4u-24\)?

Here are the steps:



\[20{u}^{2}+4u-24\]

1
Find the Greatest Common Factor (GCF).
GCF = \(4\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[4(\frac{20{u}^{2}}{4}+\frac{4u}{4}-\frac{24}{4})\]

3
Simplify each term in parentheses.
\[4(5{u}^{2}+u-6)\]

4
Split the second term in \(5{u}^{2}+u-6\) into two terms.
\[4(5{u}^{2}+6u-5u-6)\]

5
Factor out common terms in the first two terms, then in the last two terms.
\[4(u(5u+6)-(5u+6))\]

6
Factor out the common term \(5u+6\).
\[4(5u+6)(u-1)\]

Done
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