Problem of the Week

Updated at Feb 24, 2025 4:02 PM

How would you solve \(\frac{4{n}^{2}}{3-4n}=-4\)?

Below is the solution.



\[\frac{4{n}^{2}}{3-4n}=-4\]

1
Multiply both sides by \(3-4n\).
\[4{n}^{2}=-4(3-4n)\]

2
Divide both sides by \(-4\).
\[-{n}^{2}=3-4n\]

3
Move all terms to one side.
\[{n}^{2}+3-4n=0\]

4
Factor \({n}^{2}+3-4n\).
\[(n-3)(n-1)=0\]

5
Solve for \(n\).
\[n=3,1\]

Done
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