Problem of the Week

Updated at Jun 9, 2025 11:22 AM

How would you find the factors of \(4{v}^{2}-4v-8\)?

Below is the solution.



\[4{v}^{2}-4v-8\]

1
Find the Greatest Common Factor (GCF).
GCF = \(4\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[4(\frac{4{v}^{2}}{4}+\frac{-4v}{4}-\frac{8}{4})\]

3
Simplify each term in parentheses.
\[4({v}^{2}-v-2)\]

4
Factor \({v}^{2}-v-2\).
\[4(v-2)(v+1)\]

Done
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