Problem of the Week

Updated at Apr 20, 2026 5:13 PM

This week we have another algebra problem:

How would you find the factors of \(10{m}^{2}+28m-6\)?

Let's start!



\[10{m}^{2}+28m-6\]

1
Find the Greatest Common Factor (GCF).
GCF = \(2\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[2(\frac{10{m}^{2}}{2}+\frac{28m}{2}-\frac{6}{2})\]

3
Simplify each term in parentheses.
\[2(5{m}^{2}+14m-3)\]

4
Split the second term in \(5{m}^{2}+14m-3\) into two terms.
\[2(5{m}^{2}+15m-m-3)\]

5
Factor out common terms in the first two terms, then in the last two terms.
\[2(5m(m+3)-(m+3))\]

6
Factor out the common term \(m+3\).
\[2(m+3)(5m-1)\]

Done
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