Problem of the Week

Updated at Sep 8, 2025 9:35 AM

This week's problem comes from the calculus category.

How can we solve for the derivative of \(14p+\sqrt{p}\)?

Let's begin!



\[\frac{d}{dp} 14p+\sqrt{p}\]

1
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[14+\frac{1}{2\sqrt{p}}\]

Done
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