Problem of the Week

Updated at Jun 8, 2026 8:16 AM

For this week we've brought you this equation problem.

How would you solve the equation \(4v-4+\frac{{v}^{2}}{6}=\frac{19}{2}\)?

Here are the steps:



\[4v-4+\frac{{v}^{2}}{6}=\frac{19}{2}\]

1
Multiply both sides by \(6\).
\[24v-24+{v}^{2}=57\]

2
Move all terms to one side.
\[24v-24+{v}^{2}-57=0\]

3
Simplify  \(24v-24+{v}^{2}-57\)  to  \(24v-81+{v}^{2}\).
\[24v-81+{v}^{2}=0\]

4
Factor \(24v-81+{v}^{2}\).
\[(v-3)(v+27)=0\]

5
Solve for \(v\).
\[v=3,-27\]

Done