Problem of the Week

Updated at Feb 10, 2020 5:21 PM

For this week we've brought you this equation problem.

How can we solve the equation $$4(3-\frac{5}{{q}^{2}})=-8$$?

Here are the steps:

$4(3-\frac{5}{{q}^{2}})=-8$

 1 Divide both sides by $$4$$.$3-\frac{5}{{q}^{2}}=-\frac{8}{4}$2 Simplify  $$\frac{8}{4}$$  to  $$2$$.$3-\frac{5}{{q}^{2}}=-2$3 Subtract $$3$$ from both sides.$-\frac{5}{{q}^{2}}=-2-3$4 Simplify  $$-2-3$$  to  $$-5$$.$-\frac{5}{{q}^{2}}=-5$5 Multiply both sides by $${q}^{2}$$.$-5=-5{q}^{2}$6 Divide both sides by $$-5$$.$1={q}^{2}$7 Take the square root of both sides.$\pm \sqrt{1}=q$8 Simplify  $$\sqrt{1}$$  to  $$1$$.$\pm 1=q$9 Switch sides.$q=\pm 1$Doneq=1,-1