Problem of the Week

Updated at Dec 14, 2020 1:02 PM

How would you solve \(\frac{\frac{4}{5}{t}^{2}}{5}=\frac{4}{25}\)?

Below is the solution.



\[\frac{\frac{4}{5}{t}^{2}}{5}=\frac{4}{25}\]

1
Simplify  \(\frac{4}{5}{t}^{2}\)  to  \(\frac{4{t}^{2}}{5}\).
\[\frac{\frac{4{t}^{2}}{5}}{5}=\frac{4}{25}\]

2
Simplify  \(\frac{\frac{4{t}^{2}}{5}}{5}\)  to  \(\frac{4{t}^{2}}{5\times 5}\).
\[\frac{4{t}^{2}}{5\times 5}=\frac{4}{25}\]

3
Simplify  \(5\times 5\)  to  \(25\).
\[\frac{4{t}^{2}}{25}=\frac{4}{25}\]

4
Multiply both sides by \(25\).
\[4{t}^{2}=\frac{4}{25}\times 25\]

5
Cancel \(25\).
\[4{t}^{2}=4\]

6
Divide both sides by \(4\).
\[{t}^{2}=1\]

7
Take the square root of both sides.
\[t=\pm \sqrt{1}\]

8
Simplify  \(\sqrt{1}\)  to  \(1\).
\[t=\pm 1\]

Done
Cymath foriOSAndroid