Problem of the Week

Updated at Mar 17, 2025 2:56 PM

For this week we've brought you this equation problem.

How would you solve \(\frac{8z(z+2)}{5}=\frac{64}{5}\)?

Here are the steps:



\[\frac{8z(z+2)}{5}=\frac{64}{5}\]

1
Multiply both sides by \(5\).
\[8z(z+2)=64\]

2
Expand.
\[8{z}^{2}+16z=64\]

3
Move all terms to one side.
\[8{z}^{2}+16z-64=0\]

4
Factor out the common term \(8\).
\[8({z}^{2}+2z-8)=0\]

5
Factor \({z}^{2}+2z-8\).
\[8(z-2)(z+4)=0\]

6
Solve for \(z\).
\[z=2,-4\]

Done