Problem of the Week

Updated at Jan 5, 2026 3:52 PM

How would you solve the equation \({(4+2(3-t))}^{2}=0\)?

Below is the solution.



\[{(4+2(3-t))}^{2}=0\]

1
Factor out the common term \(2\).
\[{(2(2+3-t))}^{2}=0\]

2
Simplify  \(2+3-t\)  to  \(5-t\).
\[{(2(5-t))}^{2}=0\]

3
Use Multiplication Distributive Property: \({(xy)}^{a}={x}^{a}{y}^{a}\).
\[{2}^{2}{(5-t)}^{2}=0\]

4
Simplify  \({2}^{2}\)  to  \(4\).
\[4{(5-t)}^{2}=0\]

5
Divide both sides by \(4\).
\[{(5-t)}^{2}=0\]

6
Take the square root of both sides.
\[5-t=0\]

7
Subtract \(5\) from both sides.
\[-t=-5\]

8
Multiply both sides by \(-1\).
\[t=5\]

Done
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